SELECT CTG.*,IMGCTG.image_id as is_empty FROM `categories` AS CTG LEFT JOIN `image_category` AS IMGCTG ON IMGCTG.category_id=CTG.ID WHERE CTG.parent_id='1' AND CTG.active=1 AND CTG.title NOT LIKE 'private' GROUP BY CTG.ID ORDER BY order_num [nativecode=1055 ** Expression #10 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'viter_viter.IMGCTG.image_id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by]
All photos of this model / Все фото этой модели
Какая прелесть)